Monday, October 17, 2016

Solve m₁g-t=m₁a₁, m₂g-½t=m₂a₂, m₃g-½t=m₃a₃, -2a₁=a₂+a₃, for t,a₁,a₂,a₃, where t is a tension of the cord of the pulley A


Solve
m₁g-t=m₁a₁,
m₂g-½t=m₂a₂,
m₃g-½t=m₃a₃,
-2a₁=a₂+a₃,
for t,a₁,a₂,a₃
where t is a tension of the cord of the pulley A

Tuesday, July 5, 2016

Problem: The net forces acting on masses are equal to each other but unknown

Problem: The net forces acting on masses are equal to each other but unknown. Masses are unknown too. Resulting accelerations a₁, a₂ are known. Find the acceleration if the same force acts on the both masses coupled together. First derive a formula for the unknown acceleration in terms of the known accelerations. Calculate the solution for a₁=3m/s², a₂=6m/s².

The force F₁ produces an unknown acceleration by acting on the unknown mass

The force F₁ produces an unknown acceleration by acting on the unknown mass. The force F₂ produces the same unknown acceleration, by acting on the second unknown mass. Find the force which produces the same acceleration, by acting on these masses coupled together as a whole.
a) Derive a formula for the desirable force in terms of known forces.
b) Calculate the solution if F₁=3N, F₂=6N.

An unknown net force acting on the known mass m₁ produces an unknown acceleration

Monday, February 22, 2016

Физика - Открытая группа - Physics - Public Group

Физика
Общественная группа - Открытая группа - общедоступная группа
Для обсуждения на русском языке любых проблем физики, как науки, инженерной и бытовой практики, а также предмета преподавания на всех уровнях.
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